Cottonwood is a city in Yavapai County, Arizona, United States. According to the 2010 census, the population of the city is 11,265. Cottonwood is located at 34°43′56″N 112°1′7″W / 34.73222°N 112.01861°W / 34.73222; -112.01861 (34.7321, -112.0186). According to the United States Census Bureau, the city has a total area of 10.7 square miles (28 km2), all land. At the 2000 census there were 9,179 people, 3,983 households and 2,369 families in the city. The population density was 860.3 inhabitants per square mile (332.2/km2). There were 4,427 housing units at an average density of 414.9 per square mile (160.2/km2). The racial makeup of the city was 85.2% White, 0.5% Black or African American, 1.6% Native American, 0.4% Asian, <0.1% Pacific Islander, 9.7% from other races, and 2.6% from two or more races. 20.5% of the population were Hispanic or Latino of any race. Of the 3,983 households 25.3% had children under the age of 18 living with them, 44.5% were married couples living together, 10.8% had a female as Head of Household with no Husband present, and 40.5% were non-families. 34.4% of households were one person and 19.1% were one person aged 65 or older. The average household size was 2.27 and the average family size was 2.90. More information...
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