0.999… (Chinese Wikipedia)

Analysis of information sources in references of the Wikipedia article "0.999…" in Chinese language version.

refsWebsite

Global rank Chinese rank

7web.archive.org

1^st place

1st-and.ac.uk

3,503^rd place

2,468^th place

1maa.org

3,479^th place

4,890^th place

1webcitation.org

24^th place

29^th place

1faqs.org

4,871^st place

2,410^th place

1wikipedia.org

low place

1straightdope.com

2,317^th place

2,492^nd place

1blizzard.com

8,880^th place

2,717^th place

1uwo.ca

5,491^st place

5,974^th place

1nott.ac.uk

low place

1microsoft.com

153^rd place

238^th place

blizzard.com

us.blizzard.com

Blizzard Entertainment Announces .999~（Repeating）= 1. Press Release. Blizzard Entertainment. 2004-04-01 [2006-09-03]. （原始内容存档于2009-11-04）.

faqs.org

由Richman（p.396）观察到。Hans de Vreught. sci.math FAQ: Why is 0.9999… = 1?. 1994 [2006-06-29]. （原始内容存档于2007-09-29）.

maa.org

Mathematics Magazine:Guidelines for Authors. Mathematical Association of America. [2006-08-23]. （原始内容存档于2012-02-19）.

microsoft.com

msdn.microsoft.com

Floating point types. MSDN C# Language Specification. [2006-08-29]. （原始内容存档于2006-08-24）.

nott.ac.uk

maths.nott.ac.uk

Berlekamp, Conway, and Guy（pp.79–80, 307–311）讨论了1和¹/₃，也简略地提到了¹/_ω。对於0.111…₂的博弈可以直接从伯利坎普法则得出，在以下的网站有所讨论：A. N. Walker. Hackenstrings and the 0.999…? 1 FAQ. 1999 [2006-06-29]. （原始内容存档于2006-06-16）.

st-and.ac.uk

www-gap.dcs.st-and.ac.uk

J J O'Connor and E F Robertson. History topic: The real numbers: Stevin to Hilbert. MacTutor History of Mathematics. 2005-10 [2006-08-30]. （原始内容存档于2007-09-29）.

straightdope.com

Cecil Adams（英语：Cecil Adams）. An infinite question: Why doesn't .999~ = 1?. The Straight Dope（英语：The Straight Dope）. Chicago Reader（英语：Chicago Reader）. 2003-07-11 [2006-09-06]. （原始内容存档于2012-01-10）.

uwo.ca

publish.uwo.ca

John L. Bell. An Invitation to Smooth Infinitesimal Analysis (PDF). 2003 [2006-06-29]. （原始内容存档 (PDF)于2006-06-29）.

web.archive.org

J J O'Connor and E F Robertson. History topic: The real numbers: Stevin to Hilbert. MacTutor History of Mathematics. 2005-10 [2006-08-30]. （原始内容存档于2007-09-29）.
由Richman（p.396）观察到。Hans de Vreught. sci.math FAQ: Why is 0.9999… = 1?. 1994 [2006-06-29]. （原始内容存档于2007-09-29）.
Cecil Adams（英语：Cecil Adams）. An infinite question: Why doesn't .999~ = 1?. The Straight Dope（英语：The Straight Dope）. Chicago Reader（英语：Chicago Reader）. 2003-07-11 [2006-09-06]. （原始内容存档于2012-01-10）.
Blizzard Entertainment Announces .999~（Repeating）= 1. Press Release. Blizzard Entertainment. 2004-04-01 [2006-09-03]. （原始内容存档于2009-11-04）.
John L. Bell. An Invitation to Smooth Infinitesimal Analysis (PDF). 2003 [2006-06-29]. （原始内容存档 (PDF)于2006-06-29）.
Berlekamp, Conway, and Guy（pp.79–80, 307–311）讨论了1和¹/₃，也简略地提到了¹/_ω。对於0.111…₂的博弈可以直接从伯利坎普法则得出，在以下的网站有所讨论：A. N. Walker. Hackenstrings and the 0.999…? 1 FAQ. 1999 [2006-06-29]. （原始内容存档于2006-06-16）.
Floating point types. MSDN C# Language Specification. [2006-08-29]. （原始内容存档于2006-08-24）.

webcitation.org

Mathematics Magazine:Guidelines for Authors. Mathematical Association of America. [2006-08-23]. （原始内容存档于2012-02-19）.

wikipedia.org

en.wikipedia.org

Cecil Adams（英语：Cecil Adams）. An infinite question: Why doesn't .999~ = 1?. The Straight Dope（英语：The Straight Dope）. Chicago Reader（英语：Chicago Reader）. 2003-07-11 [2006-09-06]. （原始内容存档于2012-01-10）.